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1. MISC1.签到扫码得到flag
2.签个到base85解码,base32解码,base64解码，得到微信号（很明显看出）

上面那个很明显看出是王文旭师哥写的，但是在师哥们在实验室出题的时候，我真没想">
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                <h1 id="2022年春季赛WP"><a href="#2022年春季赛WP" class="headerlink" title="2022年春季赛WP"></a>2022年春季赛WP</h1><p>[TOC]</p>
<h2 id="1-MISC"><a href="#1-MISC" class="headerlink" title="1. MISC"></a>1. MISC</h2><h3 id="1-签到"><a href="#1-签到" class="headerlink" title="1.签到"></a>1.签到</h3><p>扫码得到flag</p>
<h3 id="2-签个到"><a href="#2-签个到" class="headerlink" title="2.签个到"></a>2.签个到</h3><p>base85解码,base32解码,base64解码，得到微信号（很明显看出）</p>
<blockquote>
<p>上面那个很明显看出是王文旭师哥写的，但是在师哥们在实验室出题的时候，我真没想出来，被王师哥坑道了，我以为是加密…….</p>
</blockquote>
<p>微信搜索好友，查看个性签名得到flag ,也是因为当时我们觉得这个签到，有点离谱，就又出了一道真签到。</p>
<h3 id="3-The-flag-is-under-the-picture"><a href="#3-The-flag-is-under-the-picture" class="headerlink" title="3.The flag is under the picture"></a>3.The flag is under the picture</h3><p>这一道题目，思路来自于在过去做过的一道，flag_under_the_picture和山东省科技节的一道大赛杂项。其实，在设计的时候稍微降了下难度，原题真的是图片隐写，但是考虑这次考察了一些其他内容，就在不在这一道题考察图片隐写，至于山东科技节的真题当时flag是两部分，一部分在文字类型里，另一部分则是隐藏文字。</p>
<p>这个算是一个签到(信息收集？)难度应该不大。</p>
<blockquote>
<p>1 under_the_picture，图片在word里的位置有很多种，环绕好像是最常见的，当时如果选择浮在文字之上就可以在图片下隐藏一些信息。</p>
<p>2 word实际上可以看做一个压缩包，我们可以在里面秘密的添加一些文件</p>
<p>3 在word下，我们可以更改字体格式为任意值，虽然这在显示中是默认值，但是字体名确实是你自定义的那些</p>
<p>4  隐藏文字，可以在word中设置显示隐藏文字</p>
</blockquote>
<p>flag{this_is_a_Sign_in_You_are_well}</p>
<blockquote>
<p>在这边师哥道歉下，我这次出题还是考虑不周，文档里面可以找到的所有信息和最后剩余的其实差了一个下划线_ ,虽然这种少下划线的平时做题也有，但这次我确实也没考虑这个，给师弟们放的Hint里面也误导了一些师弟…..</p>
</blockquote>
<h3 id="4-Virus-Killer"><a href="#4-Virus-Killer" class="headerlink" title="4.Virus_Killer"></a>4.Virus_Killer</h3><p>这是一道让所有 参赛选手都可以参与的题目，有谁能不喜欢我的世界呢？</p>
<p>我修改了包括终末之诗在内的一些内容，flag就在终末之诗里面，击败末影龙就能得到<strong>flag</strong>。</p>
<p>当然我觉得正常应该没人会是通过 杀死末影龙看到终末之诗吧，在配置文件里有一个 病毒杀手.jar用压缩包格式打开可以在里面找到终末之诗的配置文件，end</p>
<p>你会得到这一串</p>
<pre class="line-numbers language-none"><code class="language-none">§3恭喜你
§2PLAYERNAME
§3成功击败了冠状病毒
§2来到了这里
§3现在
§2你将获得你的奖励
§3仔细看
§6ZmxhZ3tUaGVfdmlydXNfd2lsbF9wYXNzfQ&#x3D;&#x3D;<span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<p>base64解码得到flag flag{The_virus_will_pass}</p>
<h3 id="5-拆红包"><a href="#5-拆红包" class="headerlink" title="5.拆红包"></a>5.拆红包</h3><p>Linux下binwalk分离，得到一个txt（41,21,33,45,11,14,13）<br>使用010改变图片高度(WORD Y_image)，下方为一个鼓，由此联想到敲击码打开文件，下面放一张敲击码图</p>
<p><img src="https://wzn0410.oss-cn-beijing.aliyuncs.com/img/%E5%A4%8D%E4%B9%A0/202203271009459.png"></p>
<h3 id="6-兔死who悲"><a href="#6-兔死who悲" class="headerlink" title="6.兔死who悲"></a>6.兔死who悲</h3><p>这个题，应该是来自王文旭师哥，兔吗，这很明显说的是rabbit密码，在图片中有一句我需要爆破，在比赛过程中，我们也放出了hint给出了zip-crc-cracker-master的下载地址</p>
<p>其实做出来的数量较我们的预期少了，因为提示给的很充足，使用binwalk -e分解图片可以得到flag.txt文件，这个是Rabbit加密的密文文件，在同时还存在一个加密文件夹，使用爆破跑是跑不出来的，这里需要crc碰撞</p>
<p>可以通过python3 crack.py key.zip简单得到解密秘钥(0_0)，解密得到flag</p>
<pre class="line-numbers language-none"><code class="language-none">flag&#123;u_really_know_rabbits_and_crack&#125;<span aria-hidden="true" class="line-numbers-rows"><span></span></span></code></pre>

<h3 id="7-黑化的维亚"><a href="#7-黑化的维亚" class="headerlink" title="7.黑化的维亚"></a>7.黑化的维亚</h3><p>用stegsolve打开，查看不同色域下的图片</p>
<p><img src="https://s1.ax1x.com/2022/03/27/qwIgDf.png" alt="qwIgDf.png"></p>
<p>可以在相机的属性中找到序列号abcd，用abcd作为秘钥加密一次就得到flag。</p>
<pre class="line-numbers language-none"><code class="language-none">flag&#123;wowowoheihuale!123&#125;<span aria-hidden="true" class="line-numbers-rows"><span></span></span></code></pre>

<h3 id="8-Retrieve-the-passcode"><a href="#8-Retrieve-the-passcode" class="headerlink" title="8.Retrieve_the_passcode"></a>8.Retrieve_the_passcode</h3><p>附件为一个rar文件和scatter.txt，从文件名入手，010内直接更改编辑。本题的scatter意思为散点，在MATLAB 为函数 在向量 x 和 y 指定的位置创建一个包含圆形的散点图。内数据格式为num,num,num;<br>使用Python处理数据，画出散点图即为压缩包密码（或直接暴力）</p>
<pre class="line-numbers language-python" data-language="python"><code class="language-python"><span class="token keyword">import</span> matplotlib<span class="token punctuation">.</span>pyplot <span class="token keyword">as</span> plt
<span class="token keyword">import</span> numpy <span class="token keyword">as</span> np
<span class="token keyword">import</span> math
lines <span class="token operator">=</span> <span class="token builtin">open</span><span class="token punctuation">(</span><span class="token string">"scatter.txt"</span><span class="token punctuation">,</span> <span class="token string">"r"</span><span class="token punctuation">)</span><span class="token punctuation">.</span>readlines<span class="token punctuation">(</span><span class="token punctuation">)</span>
X <span class="token operator">=</span> <span class="token punctuation">[</span><span class="token punctuation">]</span>
Y <span class="token operator">=</span> <span class="token punctuation">[</span><span class="token punctuation">]</span>
<span class="token keyword">for</span> line <span class="token keyword">in</span> lines<span class="token punctuation">:</span>
    x<span class="token punctuation">,</span>y<span class="token punctuation">,</span>z <span class="token operator">=</span> line<span class="token punctuation">.</span>split<span class="token punctuation">(</span><span class="token string">":"</span><span class="token punctuation">)</span>
    X<span class="token punctuation">.</span>append<span class="token punctuation">(</span>x<span class="token punctuation">)</span>
    Y<span class="token punctuation">.</span>append<span class="token punctuation">(</span>y<span class="token punctuation">)</span>
plt<span class="token punctuation">.</span>scatter<span class="token punctuation">(</span>X<span class="token punctuation">,</span> Y<span class="token punctuation">,</span> s<span class="token operator">=</span><span class="token number">1</span><span class="token punctuation">,</span> color<span class="token operator">=</span><span class="token string">'red'</span><span class="token punctuation">)</span>
plt<span class="token punctuation">.</span>xlim<span class="token punctuation">(</span><span class="token punctuation">(</span><span class="token operator">-</span><span class="token number">20</span><span class="token punctuation">,</span> <span class="token number">50</span><span class="token punctuation">)</span><span class="token punctuation">)</span>
plt<span class="token punctuation">.</span>ylim<span class="token punctuation">(</span><span class="token punctuation">(</span><span class="token operator">-</span><span class="token number">20</span><span class="token punctuation">,</span> <span class="token number">50</span><span class="token punctuation">)</span><span class="token punctuation">)</span>
plt<span class="token punctuation">.</span>show<span class="token punctuation">(</span><span class="token punctuation">)</span><span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<p>打开pdf为一串摩斯密码，解码得flag</p>
<h3 id="9-0和1的故事"><a href="#9-0和1的故事" class="headerlink" title="9.0和1的故事"></a>9.0和1的故事</h3><p>这个题的话我是套了以前做过的几个题，给大家添麻烦了，如果我没猜错的话，不少师弟师妹应该做过一个01字符串生成二维码的题目，师哥为了不让大家这么快获得flag，在外面套了一个base64转图片。因为得到是图片的形式了，后面的处理方式就看大家的脑洞。</p>
<p>基本上就是识图，生成01串，然后将他还原成二维码，这里还有个坑，我专门把标志位那块的01都换成了0，了解二维码的形状就能很轻松的将其复原。</p>
<p>这是一个0,1字符串生成二维码的脚本，没有实现的师弟师妹们可以看看</p>
<pre class="line-numbers language-python" data-language="python"><code class="language-python"><span class="token keyword">from</span> PIL <span class="token keyword">import</span> Image
x <span class="token operator">=</span> <span class="token number">29</span>
y <span class="token operator">=</span> <span class="token number">29</span>
im <span class="token operator">=</span> Image<span class="token punctuation">.</span>new<span class="token punctuation">(</span><span class="token string">'RGB'</span><span class="token punctuation">,</span> <span class="token punctuation">(</span>x<span class="token punctuation">,</span> y<span class="token punctuation">)</span><span class="token punctuation">)</span>
white <span class="token operator">=</span> <span class="token punctuation">(</span><span class="token number">255</span><span class="token punctuation">,</span> <span class="token number">255</span><span class="token punctuation">,</span> <span class="token number">255</span><span class="token punctuation">)</span>
black <span class="token operator">=</span> <span class="token punctuation">(</span><span class="token number">0</span><span class="token punctuation">,</span> <span class="token number">0</span><span class="token punctuation">,</span> <span class="token number">0</span><span class="token punctuation">)</span>
<span class="token keyword">with</span> <span class="token builtin">open</span><span class="token punctuation">(</span><span class="token string">'1.txt'</span><span class="token punctuation">)</span> <span class="token keyword">as</span> f<span class="token punctuation">:</span>
    <span class="token keyword">for</span> i <span class="token keyword">in</span> <span class="token builtin">range</span><span class="token punctuation">(</span>x<span class="token punctuation">)</span><span class="token punctuation">:</span>
        ff <span class="token operator">=</span> f<span class="token punctuation">.</span>readline<span class="token punctuation">(</span><span class="token punctuation">)</span>
        <span class="token keyword">for</span> j <span class="token keyword">in</span> <span class="token builtin">range</span><span class="token punctuation">(</span>y<span class="token punctuation">)</span><span class="token punctuation">:</span>
            <span class="token keyword">if</span> ff<span class="token punctuation">[</span>j<span class="token punctuation">]</span> <span class="token operator">==</span> <span class="token string">'1'</span><span class="token punctuation">:</span>
                im<span class="token punctuation">.</span>putpixel<span class="token punctuation">(</span><span class="token punctuation">(</span>i<span class="token punctuation">,</span> j<span class="token punctuation">)</span><span class="token punctuation">,</span> black<span class="token punctuation">)</span>
            <span class="token keyword">else</span><span class="token punctuation">:</span>
                im<span class="token punctuation">.</span>putpixel<span class="token punctuation">(</span><span class="token punctuation">(</span>i<span class="token punctuation">,</span> j<span class="token punctuation">)</span><span class="token punctuation">,</span> white<span class="token punctuation">)</span>
im<span class="token punctuation">.</span>resize<span class="token punctuation">(</span><span class="token punctuation">(</span><span class="token number">1000</span><span class="token punctuation">,</span> <span class="token number">1000</span><span class="token punctuation">)</span><span class="token punctuation">)</span><span class="token punctuation">.</span>show<span class="token punctuation">(</span><span class="token punctuation">)</span><span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<p>当时我在看一个类似题目的题解的时候，有位大哥是有Excel完成的…..我觉得师弟中应该没有这样干的吧</p>
<h3 id="10-有手就行"><a href="#10-有手就行" class="headerlink" title="10.有手就行"></a>10.有手就行</h3><p>B.base64.txt里的编码内容是正确的flag</p>
<p>tp文件是png图片，文件尾部有提示的base64，解出来是a=1,b=1</p>
<p>使用脚本将一大串经过多次加密的base64解出来后是:gmbh{xf1d0nf_u0_cvhlv_}</p>
<p>结合a=1,b=2和仿射密码的特征，g前一位是f，m前一位是l，以此类推可以发现是仿射密码，打开仿射密码网站，将密文输进去，然后在a处输入1，b处输入即时正确的flag</p>
<p>最终flag是：<br>flag{we1c0me_t0_bugku_30}</p>
<p>脚本：</p>
<pre class="line-numbers language-python" data-language="python"><code class="language-python"><span class="token keyword">import</span> base64
a <span class="token operator">=</span> <span class="token builtin">open</span><span class="token punctuation">(</span><span class="token string">'B.base64.txt'</span><span class="token punctuation">,</span><span class="token string">'r'</span><span class="token punctuation">,</span>encoding<span class="token operator">=</span><span class="token string">'utf-8'</span><span class="token punctuation">)</span>
b <span class="token operator">=</span> a<span class="token punctuation">.</span>read<span class="token punctuation">(</span><span class="token punctuation">)</span>
<span class="token keyword">print</span><span class="token punctuation">(</span>b<span class="token punctuation">)</span>
<span class="token keyword">print</span><span class="token punctuation">(</span><span class="token string">'\n'</span><span class="token punctuation">)</span>
c <span class="token operator">=</span> <span class="token number">0</span>
<span class="token keyword">for</span> i <span class="token keyword">in</span> <span class="token builtin">range</span><span class="token punctuation">(</span><span class="token number">50</span><span class="token punctuation">)</span><span class="token punctuation">:</span>
    base64_de <span class="token operator">=</span> base64<span class="token punctuation">.</span>b64decode<span class="token punctuation">(</span>b<span class="token punctuation">)</span>
    <span class="token keyword">print</span><span class="token punctuation">(</span>base64_de<span class="token punctuation">)</span>
    b <span class="token operator">=</span> base64_de
    c<span class="token operator">+=</span><span class="token number">1</span>
    <span class="token keyword">print</span><span class="token punctuation">(</span>c<span class="token punctuation">)</span><span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<h2 id="2-CRYPTO"><a href="#2-CRYPTO" class="headerlink" title="2.CRYPTO"></a>2.CRYPTO</h2><h3 id="1-EzRSA"><a href="#1-EzRSA" class="headerlink" title="1.EzRSA"></a>1.EzRSA</h3><p>观察发现q是p的下一个素数，p和q相邻，考虑yafu分解n。 </p>
<p>p = 60973413304835230363868586902004006717237117044275222095949523787438821909233 </p>
<p>q = 60973413304835230363868586902004006717237117044275222095949523787438821908819 </p>
<p>接下来是正常rsa求解。 </p>
<p>exp： </p>
<pre class="line-numbers language-python" data-language="python"><code class="language-python"><span class="token keyword">from</span> Crypto<span class="token punctuation">.</span>Util<span class="token punctuation">.</span>number
<span class="token keyword">import</span> <span class="token operator">*</span> <span class="token keyword">import</span> gmpy2 
p <span class="token operator">=</span> <span class="token number">60973413304835230363868586902004006717237117044275222095949523787438821909233</span>
q <span class="token operator">=</span> <span class="token number">60973413304835230363868586902004006717237117044275222095949523787438821908819</span>
e <span class="token operator">=</span> <span class="token number">65537</span>
c <span class="token operator">=</span> <span class="token number">843360044490649635455345992345658516544479053731668488697835904926685148386299530843302273377684497428582758441622699787334991310590024330881454606434905</span> 
d<span class="token operator">=</span>gmpy2<span class="token punctuation">.</span>invert<span class="token punctuation">(</span>e<span class="token punctuation">,</span><span class="token punctuation">(</span>p<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> <span class="token operator">*</span> <span class="token punctuation">(</span>q<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span><span class="token punctuation">)</span>
n <span class="token operator">=</span> p <span class="token operator">*</span> q 
<span class="token keyword">print</span><span class="token punctuation">(</span>long_to_bytes<span class="token punctuation">(</span><span class="token builtin">pow</span><span class="token punctuation">(</span>c<span class="token punctuation">,</span>d<span class="token punctuation">,</span>n<span class="token punctuation">)</span><span class="token punctuation">)</span><span class="token punctuation">)</span>
<span class="token comment">#b'flag&#123;crypto_1s_interesting&#125;'</span><span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<h3 id="2-欧欧欧欧拉"><a href="#2-欧欧欧欧拉" class="headerlink" title="2.欧欧欧欧拉"></a>2.欧欧欧欧拉</h3><p><strong>方法一：</strong> </p>
<p>发现p，q，r均已给出，可以忽略题目中n的值，我们令n = p * q * r </p>
<p>然后就是正常求解 </p>
<pre class="line-numbers language-python" data-language="python"><code class="language-python">p <span class="token operator">=</span> <span class="token number">77708508489582208240899650131902840854815755133475819112169579073727218368043</span>
q <span class="token operator">=</span> <span class="token number">115346274621041699318908577704185761162067920193040258837922665578623979014737</span>
r <span class="token operator">=</span> <span class="token number">93166107981326026645441213611016470699177795686294207640877308859576453989929</span>
c <span class="token operator">=</span> <span class="token number">347985024400177502137432464900798540953635460694795945231855306625760961473332840686487124095862063998154167906085538622293374268339383930561570822025993330404000443189437185443891030627628783181063490300672242012327030487902957573259843362590656890086005064250511680034244728108117012676345214617621947005352669846702858611524555358875183335220452897059852086551237875454030210006489044067322848138770597108902534895893528585191491006543670911357584958970659151927090552495978448117307851072739865139783869799508202415340492688302276117064301995204992930822769693356655071714132128172897117903997013826512429240667259726064548860744384724715228197199073875301540485927036010254145447026303876803125148732898741913665524085357027</span> <span class="token number">545745800931501381715355480791801480897</span>
e <span class="token operator">=</span> <span class="token number">65537</span>
n <span class="token operator">=</span> p <span class="token operator">*</span> q <span class="token operator">*</span> r 
<span class="token keyword">from</span> Crypto<span class="token punctuation">.</span>Util<span class="token punctuation">.</span>number <span class="token keyword">import</span> <span class="token operator">*</span>
<span class="token keyword">import</span> gmpy2
d <span class="token operator">=</span> gmpy2<span class="token punctuation">.</span>invert<span class="token punctuation">(</span>e<span class="token punctuation">,</span><span class="token punctuation">(</span>p<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> <span class="token operator">*</span> <span class="token punctuation">(</span>q<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> <span class="token operator">*</span> <span class="token punctuation">(</span>r<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span><span class="token punctuation">)</span>
m <span class="token operator">=</span> <span class="token builtin">pow</span><span class="token punctuation">(</span>c<span class="token punctuation">,</span>d<span class="token punctuation">,</span>n<span class="token punctuation">)</span>
<span class="token keyword">print</span><span class="token punctuation">(</span>long_to_bytes<span class="token punctuation">(</span>m<span class="token punctuation">)</span><span class="token punctuation">)</span><span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<p><strong>方法二：</strong></p>
<p>我们也可以不更改n，利用欧拉函数的性质 </p>
<p>n = p ** 2 * q ** 3 * r ** 5 </p>
<p>phin = phi(p ** 2) * phi(q ** 3) * phi(r ** 5) = (p-1) * p * (q-1) * q * (r-1) * r**4 </p>
<p>exp: </p>
<pre class="line-numbers language-python" data-language="python"><code class="language-python">p <span class="token operator">=</span> <span class="token number">77708508489582208240899650131902840854815755133475819112169579073727218368043</span> 
q <span class="token operator">=</span> <span class="token number">115346274621041699318908577704185761162067920193040258837922665578623979014737</span> 
r <span class="token operator">=</span> <span class="token number">93166107981326026645441213611016470699177795686294207640877308859576453989929</span> 
c<span class="token operator">=</span><span class="token number">347985024400177502137432464900798540953635460694795945231855306625760961473332840686487124095862063998154167906085538622293374268339383930561570822025993330404000443189437185443891030627628783181063490300672242012327030487902957573259843362590656890086005064250511680034244728108117012676345214617621947005352669846702858611524555358875183335220452897059852086551237875454030210006489044067322848138770597108902534895893528585191491006543670911357584958970659151927090552495978448117307851072739865139783869799508202415340492688302276117064301995204992930822769693356655071714132128172897117903997013826512429240667259726064548860744384724715228197199073875301540485927036010254145447026303876803125148732898741913665524085357027545745800931501381715355480791801480897</span> 
n <span class="token operator">=</span> <span class="token number">65048551512240621993540614202950633661842586962192652824898395688184000402795957509481722751199080903392947991398273550047341785877223668123666842324877380470794846769076657730082614690182880900631464361441076132475928747991954627503106907777376357374758381806436260187733080114319610478685015082092970829089757587587993969952452971403572518192436602517670638053566510878431768966565133874950375020522410987166924387985858892891003579542248992692799457937156750952714742294212043332149687042398627353772231567346753462916369667925107827788291811362515610771720461320487626568153215009781929374220819616329622781459299058370744879472145087090461481538486760169932577206734789444604559973471107786087166188418189039013657392095931298017769281949143411358392051565393109553</span> 
e <span class="token operator">=</span> <span class="token number">65537</span> 
<span class="token keyword">from</span> Crypto<span class="token punctuation">.</span>Util<span class="token punctuation">.</span>number <span class="token keyword">import</span> <span class="token operator">*</span> 
<span class="token keyword">import</span> gmpy2 
phip <span class="token operator">=</span> <span class="token punctuation">(</span>p<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> <span class="token operator">*</span> p 
phiq <span class="token operator">=</span> <span class="token punctuation">(</span>q<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> <span class="token operator">*</span> q<span class="token operator">**</span><span class="token number">2</span> 
phir <span class="token operator">=</span> <span class="token punctuation">(</span>r<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> <span class="token operator">*</span> r<span class="token operator">**</span><span class="token number">4</span> 
phi <span class="token operator">=</span> phip <span class="token operator">*</span> phiq <span class="token operator">*</span> phir 
d <span class="token operator">=</span> gmpy2<span class="token punctuation">.</span>invert<span class="token punctuation">(</span>e<span class="token punctuation">,</span>phi<span class="token punctuation">)</span> 
<span class="token keyword">print</span><span class="token punctuation">(</span><span class="token builtin">pow</span><span class="token punctuation">(</span>c<span class="token punctuation">,</span>d<span class="token punctuation">,</span>n<span class="token punctuation">)</span><span class="token punctuation">)</span> 
<span class="token keyword">print</span><span class="token punctuation">(</span>long_to_bytes<span class="token punctuation">(</span><span class="token builtin">pow</span><span class="token punctuation">(</span>c<span class="token punctuation">,</span>d<span class="token punctuation">,</span>n<span class="token punctuation">)</span><span class="token punctuation">)</span><span class="token punctuation">)</span> 
<span class="token comment">#b'flag&#123;1_th1nk_you_get_1t&#125;'</span><span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<h3 id="3-RRRRSA"><a href="#3-RRRRSA" class="headerlink" title="3.RRRRSA"></a>3.RRRRSA</h3><p>第一段flag对N和N1 gcd可得到p，进而得到q，e进行遍历即可。 </p>
<p>第二段flag为低质数加密攻击，e=3确定，爆破即可。 </p>
<p>exp：</p>
<pre class="line-numbers language-python" data-language="python"><code class="language-python"><span class="token keyword">from</span> Crypto<span class="token punctuation">.</span>Util<span class="token punctuation">.</span>number <span class="token keyword">import</span> <span class="token operator">*</span> 
<span class="token keyword">import</span> gmpy2 
N<span class="token operator">=</span><span class="token number">8833009455505830765576231622072241161470401197695529677335107109810339880276832871604743644707359887179405543235721188241122566162151923510929667953122181</span> 
N1<span class="token operator">=</span><span class="token number">9429676793030563745207076251618678117488728061107610987225993751644166892153001760951206447627482758551907039606942492875805463671257287080808106906001851</span> 
c1<span class="token operator">=</span><span class="token number">8037069184897987958374773499995275921812115255860632996217845099273168646686370835196595250846074845406069858745424656055726674434603985267158502329518751</span> 
c2<span class="token operator">=</span><span class="token number">413575070955891267004255576879221041256089460651441473637</span> 
p <span class="token operator">=</span> gmpy2<span class="token punctuation">.</span>gcd<span class="token punctuation">(</span>N<span class="token punctuation">,</span>N1<span class="token punctuation">)</span> 
q <span class="token operator">=</span> N <span class="token operator">//</span> p 
phi <span class="token operator">=</span> <span class="token punctuation">(</span>p<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> <span class="token operator">*</span> <span class="token punctuation">(</span>q<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> 
<span class="token comment">#第一段flag枚举e </span>
<span class="token keyword">for</span> e <span class="token keyword">in</span> <span class="token builtin">range</span><span class="token punctuation">(</span><span class="token number">10000</span><span class="token punctuation">)</span><span class="token punctuation">:</span> 
    <span class="token keyword">if</span><span class="token punctuation">(</span>gmpy2<span class="token punctuation">.</span>gcd<span class="token punctuation">(</span>e<span class="token punctuation">,</span>phi<span class="token punctuation">)</span> <span class="token operator">==</span> <span class="token number">1</span><span class="token punctuation">)</span><span class="token punctuation">:</span> 
        d <span class="token operator">=</span> gmpy2<span class="token punctuation">.</span>invert<span class="token punctuation">(</span>e<span class="token punctuation">,</span><span class="token punctuation">(</span>phi<span class="token punctuation">)</span><span class="token punctuation">)</span> 
        m1 <span class="token operator">=</span> <span class="token builtin">pow</span><span class="token punctuation">(</span>c1<span class="token punctuation">,</span>d<span class="token punctuation">,</span>N<span class="token punctuation">)</span> 
        <span class="token keyword">if</span><span class="token punctuation">(</span> <span class="token string">b'flag'</span> <span class="token keyword">in</span> long_to_bytes<span class="token punctuation">(</span>m1<span class="token punctuation">)</span><span class="token punctuation">)</span><span class="token punctuation">:</span> 
            <span class="token keyword">print</span><span class="token punctuation">(</span>e<span class="token punctuation">)</span>
            flag1 <span class="token operator">=</span> long_to_bytes<span class="token punctuation">(</span>m1<span class="token punctuation">)</span> 
            <span class="token keyword">break</span> 
<span class="token comment">#第二段flag低公钥e爆破 </span>
<span class="token keyword">from</span> gmpy2 <span class="token keyword">import</span> iroot 
<span class="token keyword">import</span> libnum 
e <span class="token operator">=</span> <span class="token number">0x3</span> 
n <span class="token operator">=</span>
<span class="token number">10456335904838169914349646852830082932152130624533179855437700729986430916359910968035371355128152016750075271161129744979254605922991030753616570849211931989112941277121682363790710646503345520505931418350219098036569932546893477983585713668853372819392130314661542626399462820378837771792293945490048339575869129479058678981790418112887403292721775644533540769467889512773382494878291574262142755186374570245813695390664702262226281601456889176191920270658811753696081082528539263191477192236336112147705564796435800152614366113854349615104191052807647128834113146535639155857819697492608839941056356828288393881491</span>
k <span class="token operator">=</span> <span class="token number">0</span>
<span class="token keyword">while</span> <span class="token number">1</span><span class="token punctuation">:</span> 
    res <span class="token operator">=</span> iroot<span class="token punctuation">(</span>c2 <span class="token operator">+</span> k <span class="token operator">*</span> n<span class="token punctuation">,</span> e<span class="token punctuation">)</span> <span class="token comment"># c+k*n 开3次方根 能开3次方即可 </span>
    <span class="token keyword">if</span> <span class="token punctuation">(</span>res<span class="token punctuation">[</span><span class="token number">1</span><span class="token punctuation">]</span> <span class="token operator">==</span> <span class="token boolean">True</span><span class="token punctuation">)</span><span class="token punctuation">:</span> 
        flag2 <span class="token operator">=</span> libnum<span class="token punctuation">.</span>n2s<span class="token punctuation">(</span><span class="token builtin">int</span><span class="token punctuation">(</span>res<span class="token punctuation">[</span><span class="token number">0</span><span class="token punctuation">]</span><span class="token punctuation">)</span><span class="token punctuation">)</span> <span class="token comment"># 转为字符串 </span>
        <span class="token keyword">break</span> 
    k <span class="token operator">=</span> k <span class="token operator">+</span> <span class="token number">1</span>
    
<span class="token keyword">print</span><span class="token punctuation">(</span>flag1 <span class="token operator">+</span> flag2<span class="token punctuation">)</span> 
<span class="token comment">#e = 6709 </span>
<span class="token comment">#flag = b'flag&#123;you_get_1t!&#125;'exp: </span><span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<h3 id="4-HardRSA"><a href="#4-HardRSA" class="headerlink" title="4.HardRSA"></a>4.HardRSA</h3><p>给了hint和p，q的关系，同时又知道n，我们需要构造一个p或者q的倍数和n进行最大公约，得到p或者 </p>
<p>q。 </p>
<pre class="line-numbers language-python" data-language="python"><code class="language-python"><span class="token keyword">import</span> gmpy2 
<span class="token keyword">from</span> Crypto<span class="token punctuation">.</span>Util<span class="token punctuation">.</span>number <span class="token keyword">import</span> <span class="token operator">*</span> 
n <span class="token operator">=</span> 
<span class="token number">124993585424296591093467762244475251138759316583406117657133238536553852339669769400523449633693296145543303393465079699542574868451705092731269012710274047742582156286940702286646643111975860760853620625924935057792931203893647049496628704891431372213711245207398212732529309490088729910948745640748736955073</span> 

c <span class="token operator">=</span> 
<span class="token number">50424006770352436334712623677416186679749743823334436526623823505393135268471235757954106626248672896094704432397859493914371835003999982028550123956410656701321293836439453483634735255591270239182001956026055818185575266979363172614844927196934018068753541437103088119691563904347098094997053933889342339430</span> 

hint <span class="token operator">=</span>
<span class="token number">95947821330255050044792695953225981695564565853431169112620146574854785547870212826519391606210465121248955917602550813434927609689055640312953524952635919431672688325438812967089917271116316877318959974024993544935124710051420914708812538221556136784742855036819112563084588872068036526345880570488594712154</span> 
e <span class="token operator">=</span> <span class="token number">65537</span> 
kp <span class="token operator">=</span> hint<span class="token operator">-</span>gmpy2<span class="token punctuation">.</span>powmod<span class="token punctuation">(</span><span class="token number">1011</span><span class="token punctuation">,</span>n<span class="token punctuation">,</span>n<span class="token punctuation">)</span> 
p <span class="token operator">=</span> gmpy2<span class="token punctuation">.</span>gcd<span class="token punctuation">(</span>n<span class="token punctuation">,</span>kp<span class="token punctuation">)</span> 
q <span class="token operator">=</span> n <span class="token operator">//</span> p 
phi <span class="token operator">=</span> <span class="token punctuation">(</span>p<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span><span class="token operator">*</span><span class="token punctuation">(</span>q<span class="token operator">-</span><span class="token number">1</span><span class="token punctuation">)</span> 
d <span class="token operator">=</span> gmpy2<span class="token punctuation">.</span>invert<span class="token punctuation">(</span>e<span class="token punctuation">,</span>phi<span class="token punctuation">)</span> 
m <span class="token operator">=</span> gmpy2<span class="token punctuation">.</span>powmod<span class="token punctuation">(</span>c<span class="token punctuation">,</span>d<span class="token punctuation">,</span>n<span class="token punctuation">)</span> 
flag <span class="token operator">=</span> long_to_bytes<span class="token punctuation">(</span>m<span class="token punctuation">)</span> 
<span class="token keyword">print</span><span class="token punctuation">(</span>flag<span class="token punctuation">)</span> 
<span class="token comment">#b'flag&#123;math_1s_important&#125;'</span><span aria-hidden="true" class="line-numbers-rows"><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span><span></span></span></code></pre>

<h3 id="5-古典密码"><a href="#5-古典密码" class="headerlink" title="5.古典密码"></a>5.古典密码</h3><p><strong>猪圈密码</strong> ,<strong>圣堂武士密码</strong> ,<strong>标准银河字母</strong>解出来 FGCPFLIRTUASYON </p>
<p>最后提示说栅栏,那就栅栏解密,分栏为3时解出来 FLAGISCRYPTOFUN </p>
<p>flag{CRYPTOFUN}</p>
<h2 id="3-WEB"><a href="#3-WEB" class="headerlink" title="3.WEB"></a>3.WEB</h2>
                
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</div>

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$(function () {
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                // get the contents from search data
                var datas = $("entry", xmlResponse).map(function () {
                    return {
                        title: $("title", this).text(),
                        content: $("content", this).text(),
                        url: $("url", this).text()
                    };
                }).get();
                var $input = document.getElementById(search_id);
                var $resultContent = document.getElementById(content_id);
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                    var keywords = this.value.trim().toLowerCase().split(/[\s\-]+/);
                    $resultContent.innerHTML = "";
                    if (this.value.trim().length <= 0) {
                        return;
                    }
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                        var data_title = data.title.trim().toLowerCase();
                        var data_content = data.content.trim().replace(/<[^>]+>/g, "").toLowerCase();
                        var data_url = data.url;
                        data_url = data_url.indexOf('/') === 0 ? data.url : '/' + data_url;
                        var index_title = -1;
                        var index_content = -1;
                        var first_occur = -1;
                        // only match artiles with not empty titles and contents
                        if (data_title !== '' && data_content !== '') {
                            keywords.forEach(function (keyword, i) {
                                index_title = data_title.indexOf(keyword);
                                index_content = data_content.indexOf(keyword);
                                if (index_title < 0 && index_content < 0) {
                                    isMatch = false;
                                } else {
                                    if (index_content < 0) {
                                        index_content = 0;
                                    }
                                    if (i === 0) {
                                        first_occur = index_content;
                                    }
                                }
                            });
                        }
                        // show search results
                        if (isMatch) {
                            str += "<li><a href='" + data_url + "' class='search-result-title'>" + data_title + "</a>";
                            var content = data.content.trim().replace(/<[^>]+>/g, "");
                            if (first_occur >= 0) {
                                // cut out 100 characters
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                                var end = first_occur + 80;
                                if (start < 0) {
                                    start = 0;
                                }
                                if (start === 0) {
                                    end = 100;
                                }
                                if (end > content.length) {
                                    end = content.length;
                                }
                                var match_content = content.substr(start, end);
                                // highlight all keywords
                                keywords.forEach(function (keyword) {
                                    var regS = new RegExp(keyword, "gi");
                                    match_content = match_content.replace(regS, "<em class=\"search-keyword\">" + keyword + "</em>");
                                });

                                str += "<p class=\"search-result\">" + match_content + "...</p>"
                            }
                            str += "</li>";
                        }
                    });
                    str += "</ul>";
                    $resultContent.innerHTML = str;
                });
            }
        });
    };

    searchFunc('/shier_jinghuang/search.xml', 'searchInput', 'searchResult');
});
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